Optimal. Leaf size=44 \[ \frac{\left (B \log \left (\frac{e (a+b x)}{c+d x}\right )+A\right )^2}{2 B g i (b c-a d)} \]
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Rubi [C] time = 0.584468, antiderivative size = 304, normalized size of antiderivative = 6.91, number of steps used = 20, number of rules used = 9, integrand size = 40, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.225, Rules used = {2528, 2524, 12, 2418, 2390, 2301, 2394, 2393, 2391} \[ \frac{B \text{PolyLog}\left (2,-\frac{d (a+b x)}{b c-a d}\right )}{g i (b c-a d)}+\frac{B \text{PolyLog}\left (2,\frac{b (c+d x)}{b c-a d}\right )}{g i (b c-a d)}+\frac{\log (a+b x) \left (B \log \left (\frac{e (a+b x)}{c+d x}\right )+A\right )}{g i (b c-a d)}-\frac{\log (c+d x) \left (B \log \left (\frac{e (a+b x)}{c+d x}\right )+A\right )}{g i (b c-a d)}-\frac{B \log ^2(a+b x)}{2 g i (b c-a d)}-\frac{B \log ^2(c+d x)}{2 g i (b c-a d)}+\frac{B \log (a+b x) \log \left (\frac{b (c+d x)}{b c-a d}\right )}{g i (b c-a d)}+\frac{B \log (c+d x) \log \left (-\frac{d (a+b x)}{b c-a d}\right )}{g i (b c-a d)} \]
Antiderivative was successfully verified.
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Rule 2528
Rule 2524
Rule 12
Rule 2418
Rule 2390
Rule 2301
Rule 2394
Rule 2393
Rule 2391
Rubi steps
\begin{align*} \int \frac{A+B \log \left (\frac{e (a+b x)}{c+d x}\right )}{(35 c+35 d x) (a g+b g x)} \, dx &=\int \left (\frac{b \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )}{35 (b c-a d) g (a+b x)}-\frac{d \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )}{35 (b c-a d) g (c+d x)}\right ) \, dx\\ &=\frac{b \int \frac{A+B \log \left (\frac{e (a+b x)}{c+d x}\right )}{a+b x} \, dx}{35 (b c-a d) g}-\frac{d \int \frac{A+B \log \left (\frac{e (a+b x)}{c+d x}\right )}{c+d x} \, dx}{35 (b c-a d) g}\\ &=\frac{\log (a+b x) \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )}{35 (b c-a d) g}-\frac{\left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right ) \log (c+d x)}{35 (b c-a d) g}-\frac{B \int \frac{(c+d x) \left (-\frac{d e (a+b x)}{(c+d x)^2}+\frac{b e}{c+d x}\right ) \log (a+b x)}{e (a+b x)} \, dx}{35 (b c-a d) g}+\frac{B \int \frac{(c+d x) \left (-\frac{d e (a+b x)}{(c+d x)^2}+\frac{b e}{c+d x}\right ) \log (c+d x)}{e (a+b x)} \, dx}{35 (b c-a d) g}\\ &=\frac{\log (a+b x) \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )}{35 (b c-a d) g}-\frac{\left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right ) \log (c+d x)}{35 (b c-a d) g}-\frac{B \int \frac{(c+d x) \left (-\frac{d e (a+b x)}{(c+d x)^2}+\frac{b e}{c+d x}\right ) \log (a+b x)}{a+b x} \, dx}{35 (b c-a d) e g}+\frac{B \int \frac{(c+d x) \left (-\frac{d e (a+b x)}{(c+d x)^2}+\frac{b e}{c+d x}\right ) \log (c+d x)}{a+b x} \, dx}{35 (b c-a d) e g}\\ &=\frac{\log (a+b x) \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )}{35 (b c-a d) g}-\frac{\left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right ) \log (c+d x)}{35 (b c-a d) g}-\frac{B \int \left (\frac{b e \log (a+b x)}{a+b x}-\frac{d e \log (a+b x)}{c+d x}\right ) \, dx}{35 (b c-a d) e g}+\frac{B \int \left (\frac{b e \log (c+d x)}{a+b x}-\frac{d e \log (c+d x)}{c+d x}\right ) \, dx}{35 (b c-a d) e g}\\ &=\frac{\log (a+b x) \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )}{35 (b c-a d) g}-\frac{\left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right ) \log (c+d x)}{35 (b c-a d) g}-\frac{(b B) \int \frac{\log (a+b x)}{a+b x} \, dx}{35 (b c-a d) g}+\frac{(b B) \int \frac{\log (c+d x)}{a+b x} \, dx}{35 (b c-a d) g}+\frac{(B d) \int \frac{\log (a+b x)}{c+d x} \, dx}{35 (b c-a d) g}-\frac{(B d) \int \frac{\log (c+d x)}{c+d x} \, dx}{35 (b c-a d) g}\\ &=\frac{\log (a+b x) \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )}{35 (b c-a d) g}+\frac{B \log \left (-\frac{d (a+b x)}{b c-a d}\right ) \log (c+d x)}{35 (b c-a d) g}-\frac{\left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right ) \log (c+d x)}{35 (b c-a d) g}+\frac{B \log (a+b x) \log \left (\frac{b (c+d x)}{b c-a d}\right )}{35 (b c-a d) g}-\frac{B \operatorname{Subst}\left (\int \frac{\log (x)}{x} \, dx,x,a+b x\right )}{35 (b c-a d) g}-\frac{B \operatorname{Subst}\left (\int \frac{\log (x)}{x} \, dx,x,c+d x\right )}{35 (b c-a d) g}-\frac{(b B) \int \frac{\log \left (\frac{b (c+d x)}{b c-a d}\right )}{a+b x} \, dx}{35 (b c-a d) g}-\frac{(B d) \int \frac{\log \left (\frac{d (a+b x)}{-b c+a d}\right )}{c+d x} \, dx}{35 (b c-a d) g}\\ &=-\frac{B \log ^2(a+b x)}{70 (b c-a d) g}+\frac{\log (a+b x) \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )}{35 (b c-a d) g}+\frac{B \log \left (-\frac{d (a+b x)}{b c-a d}\right ) \log (c+d x)}{35 (b c-a d) g}-\frac{\left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right ) \log (c+d x)}{35 (b c-a d) g}-\frac{B \log ^2(c+d x)}{70 (b c-a d) g}+\frac{B \log (a+b x) \log \left (\frac{b (c+d x)}{b c-a d}\right )}{35 (b c-a d) g}-\frac{B \operatorname{Subst}\left (\int \frac{\log \left (1+\frac{d x}{b c-a d}\right )}{x} \, dx,x,a+b x\right )}{35 (b c-a d) g}-\frac{B \operatorname{Subst}\left (\int \frac{\log \left (1+\frac{b x}{-b c+a d}\right )}{x} \, dx,x,c+d x\right )}{35 (b c-a d) g}\\ &=-\frac{B \log ^2(a+b x)}{70 (b c-a d) g}+\frac{\log (a+b x) \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )}{35 (b c-a d) g}+\frac{B \log \left (-\frac{d (a+b x)}{b c-a d}\right ) \log (c+d x)}{35 (b c-a d) g}-\frac{\left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right ) \log (c+d x)}{35 (b c-a d) g}-\frac{B \log ^2(c+d x)}{70 (b c-a d) g}+\frac{B \log (a+b x) \log \left (\frac{b (c+d x)}{b c-a d}\right )}{35 (b c-a d) g}+\frac{B \text{Li}_2\left (-\frac{d (a+b x)}{b c-a d}\right )}{35 (b c-a d) g}+\frac{B \text{Li}_2\left (\frac{b (c+d x)}{b c-a d}\right )}{35 (b c-a d) g}\\ \end{align*}
Mathematica [C] time = 0.114315, size = 207, normalized size = 4.7 \[ \frac{2 B \text{PolyLog}\left (2,\frac{d (a+b x)}{a d-b c}\right )+2 B \text{PolyLog}\left (2,\frac{b (c+d x)}{b c-a d}\right )+2 A \log (a+b x)+2 B \log (a+b x) \log \left (\frac{e (a+b x)}{c+d x}\right )-2 B \log (c+d x) \log \left (\frac{e (a+b x)}{c+d x}\right )+2 B \log (a+b x) \log \left (\frac{b (c+d x)}{b c-a d}\right )+2 B \log (c+d x) \log \left (\frac{d (a+b x)}{a d-b c}\right )-B \log ^2(a+b x)-2 A \log (c+d x)-B \log ^2(c+d x)}{2 g i (b c-a d)} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.052, size = 201, normalized size = 4.6 \begin{align*} -{\frac{Aad}{i \left ( ad-bc \right ) ^{2}g}\ln \left ({\frac{be}{d}}+{\frac{e \left ( ad-bc \right ) }{ \left ( dx+c \right ) d}} \right ) }+{\frac{Abc}{i \left ( ad-bc \right ) ^{2}g}\ln \left ({\frac{be}{d}}+{\frac{e \left ( ad-bc \right ) }{ \left ( dx+c \right ) d}} \right ) }-{\frac{Bad}{2\,i \left ( ad-bc \right ) ^{2}g} \left ( \ln \left ({\frac{be}{d}}+{\frac{e \left ( ad-bc \right ) }{ \left ( dx+c \right ) d}} \right ) \right ) ^{2}}+{\frac{Bbc}{2\,i \left ( ad-bc \right ) ^{2}g} \left ( \ln \left ({\frac{be}{d}}+{\frac{e \left ( ad-bc \right ) }{ \left ( dx+c \right ) d}} \right ) \right ) ^{2}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [B] time = 1.17217, size = 232, normalized size = 5.27 \begin{align*} B{\left (\frac{\log \left (b x + a\right )}{{\left (b c - a d\right )} g i} - \frac{\log \left (d x + c\right )}{{\left (b c - a d\right )} g i}\right )} \log \left (\frac{b e x}{d x + c} + \frac{a e}{d x + c}\right ) + A{\left (\frac{\log \left (b x + a\right )}{{\left (b c - a d\right )} g i} - \frac{\log \left (d x + c\right )}{{\left (b c - a d\right )} g i}\right )} - \frac{{\left (\log \left (b x + a\right )^{2} - 2 \, \log \left (b x + a\right ) \log \left (d x + c\right ) + \log \left (d x + c\right )^{2}\right )} B}{2 \,{\left (b c g i - a d g i\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 0.493947, size = 126, normalized size = 2.86 \begin{align*} \frac{B \log \left (\frac{b e x + a e}{d x + c}\right )^{2} + 2 \, A \log \left (\frac{b e x + a e}{d x + c}\right )}{2 \,{\left (b c - a d\right )} g i} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [B] time = 1.5322, size = 170, normalized size = 3.86 \begin{align*} A \left (\frac{\log{\left (x + \frac{- \frac{a^{2} d^{2}}{a d - b c} + \frac{2 a b c d}{a d - b c} + a d - \frac{b^{2} c^{2}}{a d - b c} + b c}{2 b d} \right )}}{g i \left (a d - b c\right )} - \frac{\log{\left (x + \frac{\frac{a^{2} d^{2}}{a d - b c} - \frac{2 a b c d}{a d - b c} + a d + \frac{b^{2} c^{2}}{a d - b c} + b c}{2 b d} \right )}}{g i \left (a d - b c\right )}\right ) - \frac{B \log{\left (\frac{e \left (a + b x\right )}{c + d x} \right )}^{2}}{2 a d g i - 2 b c g i} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] time = 1.3858, size = 142, normalized size = 3.23 \begin{align*} -\frac{B i \log \left (\frac{b x + a}{d x + c}\right )^{2}}{2 \,{\left (b c g - a d g\right )}} - \frac{{\left (A i + B i\right )} \log \left ({\left | \frac{2 \, b d x + b c + a d -{\left | -b c + a d \right |}}{2 \, b d x + b c + a d +{\left | -b c + a d \right |}} \right |}\right )}{g{\left | -b c + a d \right |}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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